force forward=392*cos30
acceleratin=forcforward/massbox
on the ramp section
force up the ramp=tension*cos5
force down the ramp due to gravity=massbox*g*sin25
net force up to move up >0 or
forceuptheramp>force downthe ramp sove for tension
A large box whose mass is 30 kg rests on a
frictionless floor. A mover pushes down on
the box with a force of 392 N at an angle 30◦
below the horizontal.
What is the acceleration of the box across
the floor?
Answer in units of m/s^2
The box now rests on a frictionless ramp angled at 15◦
. The mover pulls up on a rope
attached to the box to move it up the incline.
If the rope makes an angle of 25 ◦ with
the horizontal, what is the smallest force the
mover would have to exert to move the box
up the ramp? The acceleration due to gravity
is 9.81 m/s^2
Answer in units of N.
please someone help
1 answer