A jogger is running around a circular track of circumference 480 m. If the jogger has a speed of 11 km/h, what is the magnitude of the centripetal acceleration of the jogger?

Answer 1

2πR=480 m
R=480/2π =76.4 m
v=11 km/h =11000/3600 =3.06 m/s.
a(centr)=v²/R= 3.06²/76.4 =0.12 m/s²