A jogger jogs around a circular track with a diameter of 325 m in 10. minutes. What was the jogger's average speed in m/s?
3 answers
A jogger jogs around a circular track with a diameter of 325 m in 13. minutes. What was the jogger's average speed in m/s?
pir2 = 3.14 x 325 m = 1021.0176m
t = 10mins (60seconds) = 600s
speed = d / t
= 1021.0176m/600s
= 1.7017m/s
t = 10mins (60seconds) = 600s
speed = d / t
= 1021.0176m/600s
= 1.7017m/s
pir2 = 3.14 x (325/2) m = 1656.25m
t = 13 mins (60 seconds) = 780s
speed = d / t
= 1656.25m/780s
= 2.1218m/s
Therefore, the jogger's average speed was 2.1218 m/s.
t = 13 mins (60 seconds) = 780s
speed = d / t
= 1656.25m/780s
= 2.1218m/s
Therefore, the jogger's average speed was 2.1218 m/s.