Question

A jet plane is flying at a constant altitude. At time t1=0 it has components of velocity Vx=90m/s, Vy=110m/s.At time t2=30.0s the components are Vx=-170m/s, Vy=40m/s.a).Sketch velocity vectors at t1 and t2.How do these two vectors differ?. For this time interval calculate b). The components of the average acceleration, and b). The magnitude and direction of the average acceleration.

Answer 1

Just do them separate first ax = 90-170/.5, etc
Then use pythag and tan-1 for the direction.