A cup of coffee is sitting in an airplane flying at constant speed and altitude. Mu between cup and table is .36. The plane accelerates, maintaining constant altitude. What is the maximum acceleration that the plan can have without the cup sliding backwards?

Answer 1

friction force=masscoffe*a
mu*g*masscoffee=masscoffee*a
solve for a.

Answer 2

a = mu*g*m/m
a = mu*g
a = (.36)(9.80 m/s^2)
a = 3.528 m/s^2

Is this correct?

Answer 3

yes.