Asked by Jacob

A jet leaves the airport traveling at an average rate of 564km/h. Another jet leaves the same airport traveling at a rate of 744km/h in the same direction. How long will it take for the second jet to reach the first jet
Answered by Anonymous
Did they leave at the same time?
Answered by Damon
They could not have left at the same time. Jacob-you left part of the problem out.
When you get it figured out, the distances are the same
d = rate * time
rate jet1 * time jet 1 = rate jet2 *(time jet 1 - delay)
Answered by Jacob
no the second one left a half an hour later sorry i forgot to include that
Answered by Damon
then
564 *t = 744 * (t - .5)
solve for t, the time for jet 1
then if we want the time for jet 2, subtract 1/2 hour
Answered by Jacob
564t=744(t-.5)
564t=744t-372
564t-564t=744t-372-564t
0=180t-372
0+372=180t-372+372
372=180t
372/180=180t/180
2.07=t

Is that correct?
Answered by Damon
Yes
Answered by Damon
But remember to subtract half hour for second plane
Answered by Jacob
ok thank you for all of your help
Answered by Angelica(:
564*2.07=744*2.07-.5
564*2.07=744*1.57
1167.48=1168.08
how come it doesnt equal the same thing?
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