a. KE=1/2 m v2
b. Force*distance=1/2 m v^2
a jeepney of a mass 1500kg is travelling at a speed of 20m/s (about 70km/h)
a. what is the kinetic energy of the jeepney?
b.suppose the driver suddenly steps on the brakes. if the force is 7500 newtons, what will be the distance traveled by the jeepney before it stops?
4 answers
ow btw what's the difference between the two formulas?
What is the answer?
(b) Since Kinetic Energy is equal to W, we can use the formula of W to calculate for KE.
KE= W = Fd ----> substitute the values
30,000 J = 7500 N (d) --> derive the formula to isolate the displacement
d = 30,000J / 7500 N
d = 400 m
KE= W = Fd ----> substitute the values
30,000 J = 7500 N (d) --> derive the formula to isolate the displacement
d = 30,000J / 7500 N
d = 400 m
3 answers