In this case, the probability of selecting a chocolate first is 10/30 (since there are 10 chocolates out of 30 candies).
After selecting a chocolate and eating it, there are now 29 candies left in the jar, with only 12 caramels left. So the probability of selecting a caramel next is 12/29.
To find the probability of selecting a chocolate and then a caramel, we multiply the individual probabilities:
(10/30) * (12/29) = 120/870 = 4/29
Therefore, the probability of selecting a chocolate and then a caramel is 4/29.
A jar contains 30 candies: 10 chocolates, 12 caramels, and 8 gumdrops. If one candy is randomly selected, eaten, and then a second candy is randomly selected, what is the probability of selecting a chocolate and then a caramel?
*
1/15
10/29
20/87
4/29
1 answer