The total number of candies in the jar is 30 + 10 + 12 + 8 = 60.
The probability of selecting a chocolate as the first candy is the number of chocolates divided by the total number of candies:
P(chocolate) = 10/60 = 1/6
After selecting a chocolate, there are only 59 candies left in the jar, and only 12 of them are caramels.
Therefore, the probability of selecting a caramel as the second candy given that a chocolate was already selected is:
P(caramel | chocolate) = 12/59
The probability of selecting a chocolate and then a caramel is the product of the probabilities of selecting a chocolate and then a caramel given that a chocolate was already selected:
P(chocolate and caramel) = P(chocolate) * P(caramel | chocolate)
P(chocolate and caramel) = (1/6) * (12/59)
P(chocolate and caramel) = 2/59
Therefore, the probability of selecting a chocolate and then a caramel is 2/59.
A jar contains 30 candies 10 chocolates, 12 caramels, and 8 gumdrops. If One candy is ready randomly selected eating and then a second candy is randomly selected. What is the probability of selecting a chocolate and then a caramel
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1 answer