A is partly constant and partly varies as square of B when b=1 a=4¼ and when b=7 a=196¼, (a) find the equation connection a and b (b) find a when b=square root of 15/4

2 answers

"A is partly constant and partly varies as square of B"
----> A = mB^2 + c
when b = 1, A = 4.25
4.25 = m + c

when b=7 a=196¼
196.25 = 49m + c

subtract
192 = 48m
m = 4

then 4.25 = 4 + c, c = 0.25

A = 4B^2 + .25

now you can state the actual equation, take it from here.
I don't know how to solve it
Teach me please