P = 10I^2
dP/dt = 2I dI/dt
again, plug in your numbers
units? just look at the units in the fraction that is the derivative
A. In a circuit with resistance 10 ohms, power 𝑃 (measured in watts) is equal to 10𝐼^2 , where 𝐼 is the current measured in amperes. When 𝐼=6 amperes, what is the rate of change of 𝑃 with respect to 𝐼 ?
B. If we additionally know that when 𝐼=6 , the current is increasing at 0.2 amperes per minute, at what rate (with respect to time) is power increasing at that moment?
C. What units is your answer measured in?
3 answers
Unfortunately this is my weakest topic in Calculus so far, I'm still not able to find the correct answer.
I used product rule to break up 10*I^2
Should I even be doing this? Please elaborate further if possible. (Something a 5th grader could comprehend haha)
I used product rule to break up 10*I^2
Should I even be doing this? Please elaborate further if possible. (Something a 5th grader could comprehend haha)
read up on the chain rule
If P is a function of I, and I is a function of t, then
dP/dt = dP/dI * dI/dt
If P is a function of I, and I is a function of t, then
dP/dt = dP/dI * dI/dt