Let's solve each question one by one:
Question 1
If \( \log x = 0.25 \), we want to find \( \log x 4 \):
Using the properties of logarithms, we can use the power rule:
\[ \log x 4 = \log (4^{0.25}) = 0.25 \log 4 \]
Now we need to evaluate \( \log 4 \):
Since \( 4 = 2^2 \):
\[ \log 4 = \log (2^2) = 2 \log 2 \]
Plugging this back in, we find:
\[ \log x 4 = 0.25 \cdot 2 \log 2 = 0.5 \log 2 \]
Question 2
We want to determine which of the options is equivalent to \( \log 9 \):
- \( \log(3 + 3) \) simplifies to \( \log(6) \), which is not equivalent to \( \log 9 \).
- \( 3 \log 3 \) is equal to \( \log(3^3) = \log(27) \), which is not equivalent to \( \log 9 \).
- \( 2 \log 3 \) is equal to \( \log(3^2) = \log(9) \), which is equivalent.
Therefore, the correct answer is Option #3: \( 2 \log 3 \).
Question 3
If \( \log h = 35 \), we want to find \( \log h 3 \).
Using the same method as before, we write:
\[ \log h 3 = \log(3^{35}) \]
Using the power rule:
\[ \log h 3 = 35 \log 3 \]
Question 4
To evaluate \( \log \sqrt{100} 3 \):
First, simplify \( \sqrt{100} \):
\[ \sqrt{100} = 10 \]
Thus,
\[ \log \sqrt{100} 3 = \log_{10} 3 \]
This is the evaluation, but typically in logarithm base 10, this is represented simply as \( \log 3 \).
Question 5
To find the value of \( \log 0.00001 \):
Rewrite \( 0.00001 \) in scientific notation:
\[ 0.00001 = 10^{-5} \]
Using the properties of logarithms:
\[ \log(0.00001) = \log(10^{-5}) = -5 \]
Summary of Answers:
- \( \log x 4 = 0.5 \log 2 \)
- Option #3: \( 2 \log 3 \)
- \( \log h 3 = 35 \log 3 \)
- \( \log \sqrt{100} 3 = \log 3 \)
- \( \log 0.00001 = -5 \)