Let's break down each question one at a time.
Question 1
A) If \( \log x = 0.25 \), we want to find \( \log x 4 \).
Using the power rule of logarithms, we know that:
\[ \log x 4 = \log x (2^2) = 2 \log x 2 \]
However, without knowing \( \log x 2 \), we can't solve this directly. We can convert \( \log x = 0.25 \) into an exponential form:
\[ x = 10^{0.25} = \sqrt[4]{10} \quad \text{(assuming base 10)} \]
Now, if we need \( \log x 4 \):
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Find \( \log x 2 \):
\( \log x 2 = \log (x) 2 = \frac{\log 2}{\log x} = \frac{\log 2}{0.25} = 4 \log 2 \) (again using base 10)
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Now compute \( \log x 4 \):
\[ \log x 4 = 2 \cdot 4 \log 2 = 8 \log 2 \]
For a specific numerical evaluation, we need \( \log 2 \):
Using \( \log 2 \approx 0.301 \): \[ 8 \log 2 \approx 8 \times 0.301 \approx 2.408 \]
However, since the question only asks for the expression in log form, we can give it as:
\[ \log x 4 = 8 \log 2 \]
Question 2
A) Which of the following is equivalent to \( \log 9 \)?
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Option #1: \( \log(3+3) \): \[ \log(6) \quad \text{(not equivalent)} \]
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Option #2: \( 3 \log 3 \): \[ \log(3^3) = \log(27) \quad \text{(not equivalent)} \]
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Option #3: \( 2 \log 3 \): \[ \log(3^2) = \log(9) \quad \text{(equivalent)} \]
The answer is: Option #3: \( 2 \log 3 \).
Question 3
A) If \( \log h = 35 \), we want to find \( \log h 3 \).
Using the power rule:
\[ \log h 3 = \frac{\log 3}{\log h} = \frac{\log 3}{35} \]
Since we need to keep it in a fraction form, the answer is:
\[ \log h 3 = \frac{\log 3}{35} \]
Question 4
A) Evaluate \( \log \sqrt{100} 3 \).
First, we find \( \sqrt{100} = 10 \), so we have:
\[ \log_{10} 3 \]
Since we are asked for its numerical value, we calculate:
Using \( \log_{10} 3 \approx 0.477 \): \[ \log \sqrt{100} 3 \approx 0.477 \]
Question 5
A) Find the value of \( \log 0.00001 \).
This can be rewritten as:
\[ 0.00001 = 10^{-5} \]
Now we calculate:
\[ \log 0.00001 = \log(10^{-5}) = -5 \]
So the answer is: \[ \log 0.00001 = -5 \]
Summary of Results
- \( \log x 4 = 8 \log 2 \)
- Equivalent to \( \log 9 \) is Option #3: \( 2 \log 3 \)
- \( \log h 3 = \frac{\log 3}{35} \)
- \( \log \sqrt{100} 3 \approx 0.477 \)
- \( \log 0.00001 = -5 \)