a) diameter = 2*radius = 0.15 m;
radius = 0.15/2
area = pi*radius^2
b)Work = Force*distance = 160*0.15
A hydraulic lift is used to jack a 780 kg car 15 cm off the floor. The diameter of the output piston is 15 cm, and the input force is 160 N.
a)What is the area of the input piston (in m^2)?
b)What is the work done in lifting the car 15 cm?
c)If the input piston moves 13 cm in each stroke, how high does the car move up for each stroke?
d)How many strokes are required to jack the car up 15 cm?
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