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A hydraulic jack is designed so that when the handle is pushed down 1 m, the piston raising the load moves up 0.015 m. IMA= 66....Asked by Zach
A hydraulic jack is designed so that when the handle is pushed down 1 m, the piston raising the load moves up 0.015 m.
IMA= 66.67
AMA= 26.67
Efficiency= 40%
At this efficiency, what is the force required to lift a 5000 N weight?
IMA= 66.67
AMA= 26.67
Efficiency= 40%
At this efficiency, what is the force required to lift a 5000 N weight?
Answers
Answered by
drwls
The ideal mechanical advantage is
1/0.015 = 66.67 They tell you that already.
Because of inefficiency (friction), you have to apply
1/26.67 times the lifted weight, or 187.5 N
1/0.015 = 66.67 They tell you that already.
Because of inefficiency (friction), you have to apply
1/26.67 times the lifted weight, or 187.5 N
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