η= 40% =>η =0.4
input heat Q₁=1.05•10¹⁴J
waste heat Q₂=0.6 Q₁=6.3•10¹³ J
Q₂/W=1.5
work W=0.4 Q₁=4.2•10¹³ J
(a) How much waste heat is produced by an electrical power station that uses 1.05 multiplied by 1014 J of heat input with an efficiency of 40.0%?
(b) What is the ratio of waste heat to work output?
(c) How much work is done?
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