The engine of a large ship does 2.05 multiplied by 108 J of work with an efficiency of 4.00%.
(a) How much waste heat (J) is produced?
(b) How many barrels of fuel are consumed, if each barrel produces 6.00 multiplied by 109 J of heat when burned?
2 answers
What are the dimensions of the 2.05? Meters displacement?
W=2.05•10⁸ J
η= 4.00%=> η = 0,04
Q =W/0.04=5.125•10⁹ J
Waste heat = Q - W = 5.125•10⁹-2.05•10⁸ = 4.92•10⁹ J
N= 5.125•10⁹/6•10⁹ = 0.85
η= 4.00%=> η = 0,04
Q =W/0.04=5.125•10⁹ J
Waste heat = Q - W = 5.125•10⁹-2.05•10⁸ = 4.92•10⁹ J
N= 5.125•10⁹/6•10⁹ = 0.85
1 answer