a hose pipe ejects water at a speed of 0.3m/s through a hole of area 50 cm*m.if the water strikes a wall normally, calculate the force on the wall , assuming the velocity of water normal to the wall is zero after striking?

Answer 1

The force according to the Newton’s 2 Law is
F= m•a=m•(Δv/Δt) =Δ(m•v)/ Δt
If the length of the moving stream is L and the density of water is ρ, then
F = (ρ•S•L•v)/(L/v) = ρ•S•v^2 =
=1000• 50•10^-4•(0.3)^2=0.45 N

Answer 2

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