Question
A lawn sprinkler has 40 holes,each of cross-section area 2.0×10^-² cm².it is connected to a hose-pipe of cross-section area of 1.6cm².If the speed of water in the hose-pipe is 1.2m/s,Calculate the flow rate in the hose-pipe
Answers
GPT 3.5
To calculate the flow rate in the hose-pipe, we can use the equation:
Flow rate = speed × cross-section area
The cross-section area of the hose-pipe is given as 1.6 cm². To convert this to m², we divide by 10,000 (since 1 m² = 10,000 cm²). Therefore, the cross-section area of the hose-pipe is 1.6/10,000 = 0.00016 m².
The speed of water in the hose-pipe is given as 1.2 m/s.
Plugging these values into the equation, we get:
Flow rate = 1.2 m/s × 0.00016 m² = 0.000192 m³/s
Therefore, the flow rate in the hose-pipe is 0.000192 m³/s.
Flow rate = speed × cross-section area
The cross-section area of the hose-pipe is given as 1.6 cm². To convert this to m², we divide by 10,000 (since 1 m² = 10,000 cm²). Therefore, the cross-section area of the hose-pipe is 1.6/10,000 = 0.00016 m².
The speed of water in the hose-pipe is given as 1.2 m/s.
Plugging these values into the equation, we get:
Flow rate = 1.2 m/s × 0.00016 m² = 0.000192 m³/s
Therefore, the flow rate in the hose-pipe is 0.000192 m³/s.
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