a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average acceleration

Answer 1

a = change in v / change in time
= (5.2 - 11) / 3.1
= -1.87 m/s^2

Answer 2

how much time is required for an airplane to reach its takeoff speed of 77m/s it is starts from rest and its average acceleration is 8.2 m/s

Answer 3

fgy

Answer 4

Change in time = change in v / average acceleration
change in t = (77m/s - 0 m/s) / 8.2 m/s^2
=9.39 s or 9.4 s

Answer 5

a horse bolts from its stall and 5 seconds later it is galloping at 14m/sec. What is this acceleration?