A horse pulls a cart with a force of 40lb at an angle of 30 degrees above the horizontal and moves along at a speed of 6mi/hr. A) how much work does the force do in 10 min? B) What is the average power (in horsepower) of the force?

Answer 1

A) (Force component along direction of motion) * 5280 ft = ___ ft lb

B) (Force component along direction of motion) * (speed, in ft/s) = ___ ft lb/s

Use the conversion factor 550 ft lb/s per HP. Also convert 6 mi/h to 8.8 ft/s

Answer 2

a-642,648.7029 ft.lb
b- 823.9085934 W

Answer 3

i want 1nd qus

Answer 4

(a)1.8*10^5 ft.lb (b)0.55 hp

Answer 5

Plz give the answer