A horse pulls a cart with a force of 145 newtons at an angle of 30 degrees above the horizontal and moves along at a speed of 2.5 m/s. How much work to the nearest kJ does the force do in 6 minutes?

Answer 1

d = 2.5m/s * 6min*60s/min = 900 m.

Work = F*d = 145cos30 * 900 = 443,856 J.
= 444 kJ.

Answer 2

Vector A has a magnitude of 5.00units,and B has a magnitude of 9.00units.The two vectors make an angle of 50.0degrees with each other .Find A.B.