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A horse draws a sled horizontally across a snow-covered field. The coefficient of friction between the sled and the snow is 0.1...Asked by Jim
A horse draws a sled horizontally across a snow-covered field. The coefficient of friction between the sled and the snow is 0.195, and the mass of the sled, including the load, is 202.4 kg. If the horse moves the sled at a constant speed of 1.857 m/s, what is the power needed to accomplish this?
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Answered by
drwls
Power required = Velocity x (friction force)
= V*M*g*mu
= 1.857*202.4*9.8*0.195 = 718 Watts
= V*M*g*mu
= 1.857*202.4*9.8*0.195 = 718 Watts
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