A hollow, thin-walled cylinder and a solid sphere start from rest and roll without slipping down an inclined plane of length 5.0 m. The cylinder arrives at the bottom of the plane 2.7 s after the sphere. Determine the angle between the inclined plane and the horizontal.

Answer 1

5m=1/2(5/7*(9.81*sin(theta))*((2.7*sqrt(1/2))^2)/((sqrt(5/7)-sqrt(1/2)))^2)

All you need to do is solve for sin(theta)

you do 5*((sqrt(5/7)-sqrt(1/2)))^2)*2*7/((5*9.81*((2.7*sqrt(1/2))^2))

sin(theta)=0.00746

then you do the inverse of sin(theta) to get your degree. degree should equal 0.428