A hollow spherical iron shell floats almost completely when submerged in water. The outer diameter is 50.0cm, and the density of iron is 7.87g/cm^3. Find the inner diameter.
2 answers
almost completely submerged in water.*
volume of iron = (4/3) pi (25^3) -(4/3) pi(r^3)
mass of iron = (4/3) pi(7.87) (15625-r^3)
= mass of water displaced = (4/3)pi (15625)
because density of water assumed 1 gram/cm^3
Archimedes doing the lifting so
7.87(15625-r^3) = 15625
7.87 r^3 = 6.87 (15625)
r = 23.9 cm
D = 2 r = 47.8 cm
mass of iron = (4/3) pi(7.87) (15625-r^3)
= mass of water displaced = (4/3)pi (15625)
because density of water assumed 1 gram/cm^3
Archimedes doing the lifting so
7.87(15625-r^3) = 15625
7.87 r^3 = 6.87 (15625)
r = 23.9 cm
D = 2 r = 47.8 cm
1 answer