volume of iron = (4/3)pi (Rout^3-Rin^3)
mass of iron = (1 g/cm^3)(4/3) pi Rout^3
so
density of iron = Rout^3/(Rout^3-Rin^3)
a hollow spherical iron shell floats just completely submerged in water.the outer diameter is 50 cm and the density of iron is 7.9cm cubed .find he inner diameter of the shell
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