a) impulse = Force * time of interaction
i = 950N *.0044s = 4.18N-s
don't know how to do B
A hockey player strikes a puck that is initially at rest. The force exerted by the stick on the puck is 950 N, and the stick is in contact with the puck for 4.4 ms (0.0044 s).
(a) Find the impulse imparted by the stick to the puck.
(b) What is the speed of the puck (m = 1.70 kg) just after it leaves the hockey stick?
2 answers
b) Just use the momentum equation P= mv and rearrange to use the momentum from a) and the mass they give.
P=mv
V= P/m
V= 4.18N•s/1.70kg
V= 2.6m/s
P=mv
V= P/m
V= 4.18N•s/1.70kg
V= 2.6m/s