Poisson distribution with a mean of m:
P(x) = e^(-m) m^x / x!
P(5) = e^(-3) 3^5 / 5!
I'll let you finish the computation.
A history professor finds that when he schedules an office hour at the 1030 am time slot an average of 3 students arrive. Use the poisson distribution to find the probability that in a randomly selected office hour in the 1030 am time slot exactly 5 students will arrive.
3 answers
Thank you.. It is 0.1008..
Correct!