A hiker, of mass 80 kg walks up a mountain, 700 m above sea level, to spend the night at the top in the first overnight hut. The second day she walks to the second overnight hut, 400 m above sea level. The third day she returns to her starting point, 200 m above sea level.

Question

A hiker, of mass 80 kg walks up a mountain, 700 m above sea level, to spend the night at the top in the first overnight hut. The second day she walks to the second overnight hut, 400 m above sea level. The third day she returns to her starting point, 200 m above sea level.
What is the potential energy of the hiker at the first hut (relative to sea level)?
How much potential energy has the hiker lost in the second day?

henry2, · Answer

PE1 = Mgh1 = 80*9.8*700 = ___ Joules. PE2 = Mgh2 = 80*9.8*400 = PE1-PE2 =