A hiker, of mass 80 kg walks up a mountain, 700 m above sea level, to spend the night at the top in the first overnight hut. The second day she walks to the second overnight hut, 400 m above sea level. The third day she returns to her starting point, 200 m above sea level.
How much potential energy has the hiker lost in the second day?
2 answers
m * g * Δh = 80 kg * 9.8 m/s^2 * (700 m - 400 m) = ? Joules
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