A hemispherical tank is filled with water and has a diameter of 12 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

3 answers

v = 4/3 π r^3 = 4/3 * π * 196

weight = v * 62.4 ... lbs
28229
V=
\,\,\frac{4}{3}\pi r^3
3
4

πr
3

Volume of a Sphere
V=
V=
\,\,\frac{1}{2}\left (\frac{4}{3}\pi r^3 \right)
2
1

(
3
4

πr
3
)
Volume of a Hemisphere
V=
V=
\,\,\frac{1}{2}\left (\frac{4}{3}\pi (6)^3 \right)
2
1

(
3
4

π(6)
3
)
If diameter is 12, then radius is 6.
V=
V=
\,\,452.3893\text{ }\text{ft}^3
452.3893 ft
3

452.3893\text{ }\text{ft}^3 \cdot\frac{62.4\text{ }\text{lbs}}{\text{ft}^3}=28229\text{ }\text{lbs}
452.3893 ft
3

ft
3

62.4 lbs

=28229 lbs