A heat transfer of 8.7 multiplied by 105 J is required to convert a block of ice at -12°C to water at 12°C. What was the mass of the block of ice?

Answer 1

If I'm not mistaken, it's 9.097155832 grams, which you can round as you see fit.

913.5 J = m x specific heat water x 24 degrees Celcius.

Specific heat of water is 4.184 J/(gC).

Solve for m.