A gun fires a shell at an angle of elevation of 30 degrees with a velocity of 2*10^3m/s. What is the horizontal and vertical component of the velocity? What is the range of the shell? how high will the ball rise

Answer 1

Vo = 2000m/s @ 30o.
Xo = 2000*cos30.
Yo = 2000*sin30 = 1000 m/s.

Range = Vo^2*sin(2A)/g.
Vo = 2000 m/s.
2A = 60o.
g = 9.8m/s^2.

hmax = (Y^2-Yo^2)/2g.
hmax = (0-10^6)/19.6 = 51,020 m.

Answer 2

51,020m

Answer 3

My answer for the range is 346.4

Answer 4

the answer is not explanable

Answer 5

horizontal component

Answer 6

Correct and good