First, we need to find the area of the wall before the mural is painted.
The area of the wall before is: (6x + 7)(8x + 5) = 48x^2 + 30x + 56x + 35 = 48x^2 + 86x + 35
Next, we find the area of the mural: x + 4x^2 + 5 = 4x^2 + x + 5
Now, we subtract the area of the mural from the area of the wall before to find the area of the remaining wall:
(48x^2 + 86x + 35) - (4x^2 + x + 5) = 44x^2 + 85x + 30
Therefore, the area of the remaining wall after the mural has been painted is 44x^2 + 85x + 30.
A group of art students are painting a mural on a wall the rectangular wall has the dimensions of 6X + 7 by 8x + 5 they are planning on the mural to be x + 4x2x5 + 5 what is the area of the remaining wall after the mural has been painted
1 answer
1 answer