A ground state hydrogen atom absorbs a photon of light having a wavelength of 92.30 nm. It then gives off a photon having a wavelength of 384 nm. What is the final state of the hydrogen atom? Values for physical constants can be found here.

Answer 1

Use E = hc/wavelength to calculate E for 92.30 nm line and substitute into
E = 2.180E-18J*(1/1 - 1/x^2). Solve for x. If I didn't goof x = 9.

Then find E for 384 nm line and substitute into
E = 2.180E-18J*(1/x^2 - 1/81)
Solve for x. I think x = 2.
So the 92.3 nm photon came in, raised the ground state electron in n = 1 shell to n = 9 shell. When it fell to n = 2 it released a photon of 384 nm.

Answer 2

93

Answer 3

the ground state hydrogen atom absorbs a photon of light having a wavelenth of 93.03nm. It then gives off a photon having a wavelength of 2165 nm. What is the final state of the hydrogen atom?

Answer 4

2.0