find the energy of 93.03 nm
E=plancksconstant*speedlight/lambda
Next, add that to ground state energy (look it up)
then find the energy of the emitted photon as above, then
you have the final energy state.
finalenergystat=groundstate/n^2
solve for n
A ground state hydrogen atom absorbs a photon of light having a wavelength of 93.03 nm. It then gives off a photon having a wavelength of 1005 nm. What is the final state of the hydrogen atom?
What is the equation to solve this?
1 answer