To find the value of \( b \) in the equation of the trend line \( y = 15x + b \), we first need to use one of the given points to solve for \( b \).
We have two points:
- \( (6.4, 117) \)
- \( (6.6, 120) \)
Given that the slope \( m \) of the line is \( 15 \), we can substitute one of the points into the equation to find \( b \). Let's use the point \( (6.4, 117) \).
Substituting these values into the equation gives us: \[ 117 = 15(6.4) + b \] Calculating \( 15(6.4) \): \[ 15 \times 6.4 = 96 \] Now we can substitute this back into the equation: \[ 117 = 96 + b \] To solve for \( b \), subtract \( 96 \) from both sides: \[ b = 117 - 96 = 21 \]
Thus, the value of \( b \) in the equation of the trend line is \( \boxed{21} \).