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A graph titled Monthly Sales and Advertising Costs has Advertising Costs (1,000 dollars) on the x-axis and sales (1,000 dollars...Question
A graph titled Monthly Sales and Advertising Costs has Advertising Costs (1,000 dollars) on the x-axis and sales (1,000 dollars) on the y-axis. A line goes through points (6.4, 117) and (6.6, 120).
The scatterplot and trend line show a positive correlation between advertising costs and sales.
Using the points (6.4, 117) and (6.6, 120), what is the slope of the trend line?
–15
–12
12
15
The scatterplot and trend line show a positive correlation between advertising costs and sales.
Using the points (6.4, 117) and (6.6, 120), what is the slope of the trend line?
–15
–12
12
15
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the slope of the trend line that passes through the points \((6.4, 117)\) and \((6.6, 120)\), we use the formula for the slope \(m\) of a line, which is defined as:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Here, we can assign the points as follows:
- \((x_1, y_1) = (6.4, 117)\)
- \((x_2, y_2) = (6.6, 120)\)
Now we can substitute the values into the formula:
\[
m = \frac{120 - 117}{6.6 - 6.4} = \frac{3}{0.2} = 15
\]
Thus, the slope of the trend line is **15**.
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Here, we can assign the points as follows:
- \((x_1, y_1) = (6.4, 117)\)
- \((x_2, y_2) = (6.6, 120)\)
Now we can substitute the values into the formula:
\[
m = \frac{120 - 117}{6.6 - 6.4} = \frac{3}{0.2} = 15
\]
Thus, the slope of the trend line is **15**.
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