This cannot be solved because:
In GP:
an = a1 ∙ r ⁿ ⁻ ¹
a2 = a1 ∙ r
a3 = a1 ∙ r²
a5 = a1 ∙ r⁴
a3 = 9 a1
a1 ∙ r² = 9 a1
Divide both sides by a1
r² = 9
r = ± √ 9
r = ± 3
a2 = a5 / 24
a1 ∙ r = a1 ∙ r⁴ / 24
Divide both sides by a1 ∙ r
1 = r³ / 24
Multiply both sides by 24
24 = r³
The result is:
24 = r³
24 = ( - 3 )³ = - 27
OR
24 = 3³ = 27
That is obviously not true.
A GP is such that the 3rd term is nine times the 1st term while the 2nd term is one - twenty fourth of the 5th term .Find it's fourth term.
2 answers
A G.P is such that the third term is 9times the first term, while the 2nd term is 1/24 of the 5th term. find its 4th term.