a GP has a first term of A,a common ratio of r and its 6th term is 768. another GP has a first term of a,a common ratio of 6r and its 3rd term is 3456. evaluate a and r

10 answers

term(6) = 768
ar^5 = 768

term(3) = 3456
a(6r)^2 = 3456

36ar^2 / ar^5 = 3456/768
36/r^3 = 9/2
9r^3 = 72
r^3 = 8
r = 2

go back to the first of my equations and find a

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A GO has a common ratio of a a common ratio of r and its 6th term is 768 Another GP has a first term of a a common ratio of 6r and its 3rd term is 3456 evaluate a and r

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