A golfer hits a golf ball, giving it an initial speed of 39.7 m/s at an angle of 55° above the horizontal. What is the maximum height in meters that the golf ball will achieve?

Question

A golfer hits a golf ball, giving it an initial speed of 39.7 m/s at an angle of 55° above the horizontal.  What is the maximum height in meters that the golf ball will achieve?

Henry · Answer

Vo = 39.7m/s[55o] Yo = 39.7*sin55 = 32.52 m/s. = Vertical component. Y^2 = Yo^2 + 2g*h h = (Y^2-Yo^2)/2g = (0-(32.52^2)/-19.6 = 54 m.

Anonymous · Answer

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