A golfer hits a golf ball, giving it an initial speed of 31.7 m/s at an angle of 55° above the horizontal. How far in meters will the golf ball travel horizontally before hitting the ground?

Question

A golfer hits a golf ball, giving it an initial speed of 31.7 m/s at an angle of 55° above the horizontal.  How far in meters will the golf ball travel horizontally before hitting the ground?

Henry · Accepted Answer

Vo = 31.7m/s[55o] Xo = 31.7*cos55 = 18.18 m/s. Yo = 31.7*sin55 = 25.97 m/x. Dx = Vo^2*sin(2A)/g=31.7^2*sin(110)/9.8 = 96.4 m.

bob · Answer

¯\_(ツ)_/¯ i don't knew m8

9 · Answer

Bio is better you filthy casual

julian · Answer

what is the value of A in this equation