vertical velocityinitial=35sin35
horizoal velocity=35cos35
time in air consider vertical
hf=hi+vi*t-1/2 g t^2
0=0+35sin35*t-4.8t^2 solve that with the quadratic equation..
max height is when vv=0
vv=vi*35sin35-gt=0
solve for time at max height, then
maxhdight=35sin35*t-1/2 g t^2
A golf ball leaves the club 35m/s at an teta of 35 degree above the horizontal . Find a) range b) maximum height reached c) time of flight
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