A given volume of ozone diffused from a certain apparatus in 96seconds calculate the time taken by an equal volume of carbonoxide to diffuse under the same condition?

Answer 1

R1/R2=sqrt(MW2/MW1)

But we are given the inverses of rates, (times), so

T2/T1=sqrt(MW2/MW1)

ozone MW1=16*3=48
CO MW2=28

T1=96seconds

T2 (CO)=96*sqrt(28/48) seconds