A certain volume of oxygen diffused from a given apparatus in 125 seconds. In the same conditions , the same volume of gas N, diffused in 100 seconds . Calculate the relative molecular mass of N(=16.0).

Answer 1

rate oxygen = V/125 s
rate N gas = V/100 s
molar mass O2 = 32
molar mass N = ?
mm stands for molar mass
(rate 1)/(rate 2) = sqrt (mm N/mm O2)
(V/125)/(V/100) = sqrt (mm N/32)
Solve for molar mass N.
Post your work if you get stuck.

Answer 2

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Answer 3

Solution to the question