A given mass of chlorine occupies 38cm³ at 20°c. Determine its final volume at 45°c. Pressure remains constant

Answer 1

In order to solve this problem, we need to assume the gas is behaving ideally. The equation that relates the initial and final volume and temperature is the following:

(V1 / T1) = (V2 / T2)

Where:
V1 = initial volume (38 cm³)
T1 = initial temperature (20°C) + 273.15 = 293.15 K (convert to Kelvin)
V2 = final volume (unknown)
T2 = final temperature (45°C) + 273.15 = 318.15 K (convert to Kelvin)

Now we can plug in the values and solve for V2:

(38 cm³ / 293.15 K) = (V2 / 318.15 K)

V2 = (38 cm³ * 318.15 K) / 293.15 K
V2 = 41.292 cm³ (rounded to three decimal places)

Therefore, the final volume of the given mass of chlorine at 45°C is approximately 41.292 cm³.