A certain mass of a gas occupies 200cm³at 27⁰c and the pressure of 740mmhg determine the volume of the gas at STP

Answer 1

First, let's convert the temperature to Kelvin using the formula:

T(K) = T(°C) + 273

T(K) = 27 + 273 = 300K

Next, we will use the ideal gas law formula to find the initial number of moles of gas:

PV = nRT

740 mmHg * 200 cm³ = n * 0.0821 * 300

n = (740 * 200) / (0.0821 * 300) ≈ 60.38 moles

Now, we can use the molar volume of gas at STP (22.4 L/mol) to find the volume of the gas at STP:

V(STP) = n * 22.4

V(STP) = 60.38 * 22.4 ≈ 1353.952 L

Therefore, the volume of the gas at STP is approximately 1353.952 L.