The car can intercept the balloon when the baloon is either on the way up or on the way down. You are interersted in the latter case, which gives the maximum distance of the car when thrown. The time it takes for the balloon to return to the same height that it was released is:
2*Vo*sin50/g = T = 1.876 s
The distance the car moves while the balloon is above the "throw" height is
8.00*T = 15.0 m
A girl throws a water-filled balloon at an angle of 50.0 degree(s) above the horizontal with a speed of 12.0 m/s. The horizontal component of the balloon's velocity is directed toward a car that is approaching the girl at a constant speed of 8.00 m/s. (See figure) (a) If the balloon is to hit the car at the same height at which it leaves her hand, what is the maximum distance the car can be from the girl when the balloon is thrown? You can ignore air resistance.
1 answer
1 answer