In a water balloon toss a contestant throws her balloon with a speed of 4.84 m/s at an angle of 16.5 degrees above the horizontal. Find the maximum height, the time of flight and the range of the balloon assuming her partner catches the balloon at the same height at which it was released.

Answer 1

time of flight:

hf=hi+Vi*sinTheta*t-g t^2

hf=hi find t.
now time to max height is half that time.