You either need to know calculus or a little physics.
If you have had any calculus you take the derivative , rate of change of height with time, at t = 0
dh/dt = -32 t^2 + 70
at t = 0, that is 70 ft/second
If you have taken physics you know:
if acceleration = a
then velocity = Vo + a t
and distance = intitial position + Vo t + (1/2) a t^2
in this case
a = - 32 ft/s^2 the acceleration of gravity
thus v = Vo - 32 t
and
h = 0 + Vo t - 16 t^2
which is given as h = 70 t - 16 t^2
so Vo = 70
A geyser sends a blast of boiling water high into the air. During the eruption, the height (h) (in feet) of the water (t)seconds after being forced out from the ground could be modeled by h = -16t*t + 70t.
My question is how do you find the initial velocity of the boiling water?
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